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Monday, 28 July 2025

Chemistry Solution With All Terms And Memory Game

Solution Chemistry: Henry's Law, Azeotropes, Colligative Properties

๐Ÿ’ก Solution Chemistry: Complete Guide with Advanced Topics & Memory Game

๐Ÿ” What is a Solution?

Solutions of Crackers

A solution is a homogeneous mixture composed of two or more substances. The substance present in the larger amount is usually the solvent, and the one in lesser amount is the solute.

  • Solvent: The component that dissolves the solute (e.g., water).
  • Solute: The component that gets dissolved (e.g., salt).

๐Ÿงช Henry’s Law

Henry’s Law states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the liquid at constant temperature.

Mathematical Expression: C = kP, where:

  • C is the concentration of gas in the liquid.
  • P is the partial pressure of the gas.
  • k is the Henry’s law constant.

Applications: Carbonated beverages, deep-sea diving, and anesthesia.

๐Ÿงช Types of Solutions

Depending on the physical states of solute and solvent, solutions can be:

  • Solid in liquid (e.g., sugar in water)
  • Gas in liquid (e.g., CO₂ in soda)
  • Liquid in gas (e.g., water vapor in air)

๐Ÿ”ฌ Non-Ideal Solutions

Non-ideal solutions deviate from Raoult’s Law due to differing interactions between solute and solvent molecules.

✅ Positive Deviation

  • Weaker solute-solvent interactions
  • Increased vapor pressure
  • Example: Ethanol and Acetone

✅ Negative Deviation

  • Stronger solute-solvent interactions
  • Decreased vapor pressure
  • Example: Acetone and Chloroform

♻️ Azeotropes

An azeotrope is a mixture of two or more liquids that boils at a constant temperature and composition.

  • Minimum Boiling Azeotrope: Ethanol + Water
  • Maximum Boiling Azeotrope: Hydrochloric acid + Water

They cannot be separated by simple distillation.

๐Ÿ“ Colligative Properties

  • Relative Lowering of Vapor Pressure
  • Boiling Point Elevation
  • Freezing Point Depression
  • Osmotic Pressure

These depend on the number of solute particles, not their identity.

๐Ÿงฎ van’t Hoff Factor (i)

Formula: i =

observed valuecalculated value

It adjusts for dissociation/association of solutes. For example, NaCl dissociates into Na⁺ and Cl⁻, so i ≈ 2.

Graphical view of Positive and negative Deviation

Positive & Negative Deviations

Graphical view of Depression in Freezing Point

Depression in Freezing Point

Graphical view of Elevation in Boiling Point

Elevation in Boiling Point

๐ŸŽฎ Memory Puzzle Game

Match the concepts and their terms by clicking below:

๐ŸŽฎ Play Colligative Properties Memory Game

✅ Conclusion | เคจिเคท्เค•เคฐ्เคท

This article includes basic to advanced level content from solubility concepts to memory games.

๐Ÿ“Œ Bookmark this article to revise before exams and Olympiads!

Colligative Properties IIT - JEE level Problems

Question 1

A solution contains 5.85 g of NaCl in 100 g of water. Calculate the depression in freezing point. (Kf = 1.86 K kg/mol)

Answer: ฮ”Tf = 3.72 K (Using van't Hoff factor i = 2)

Question 2

A 0.1 molal solution of urea (non-electrolyte) causes a depression in freezing point of 0.186 K. What is the molal depression constant of the solvent?

Answer: Kf = ฮ”Tf/m = 0.186 / 0.1 = 1.86 K kg/mol

Question 3

Which of the following 0.01 molal aqueous solution will have the lowest freezing point?
A. NaCl
B. Glucose
C. BaCl2
D. Urea

Answer: C. BaCl2 (i = 3, highest van't Hoff factor)

Question 4

Calculate the osmotic pressure of a 0.1 M solution of glucose at 27°C. (R = 0.0821 L atm/mol K)

Answer: ฯ€ = nRT/V = 0.1 × 0.0821 × 300 = 2.46 atm

Question 5

A solution containing 1 g of solute in 100 g of water gave a boiling point elevation of 0.52°C. If Kb = 0.52 K kg/mol, find the molar mass of the solute.

Answer: M = (1000 × 1 × 0.52) / (100 × 0.52) = 100 g/mol

Question 6

1.8 g of glucose (C6H12O6) is dissolved in 100 g of water. Calculate the depression in freezing point. (Kf = 1.86 K kg/mol)

Answer: ฮ”Tf = 0.186 K

Question 7

Which of the following shows the highest boiling point elevation?
A. 0.1 M NaCl
B. 0.1 M BaCl2
C. 0.1 M Glucose
D. 0.1 M AlCl3

Answer: D. AlCl3 (i = 4, highest number of particles)

Question 8

A 1 molal solution of a non-volatile solute has a freezing point depression of 1.86°C. What will be the freezing point of this solution?

Answer: 0 - 1.86 = -1.86°C

Question 9

Osmotic pressure of a solution at 300 K is 2.46 atm. Find the concentration of solute (R = 0.0821 L atm/mol K).

Answer: C = ฯ€ / RT = 2.46 / (0.0821 × 300) = 0.1 M

Question 10

Which property is used to determine molar mass of a solute in dilute solution?
A. Surface tension
B. Colligative property
C. Viscosity
D. Refractive index

Answer: B. Colligative property

Question 11

3 g of a non-volatile solute dissolved in 100 g water produces a boiling point elevation of 0.3°C. Molar mass of solute is 60. What is Kb?

Answer: Kb = ฮ”Tb × M × 1000 / (W × m) = 0.3 × 60 × 1000 / (3 × 100) = 6 K kg/mol

Question 12

Identify the colligative property which is not affected by ionization:
A. Relative lowering of vapor pressure
B. Boiling point elevation
C. Freezing point depression
D. None of these

Answer: D. None of these (all are affected by van’t Hoff factor)

Question 13

A 0.1 M solution of MgSO4 behaves as 0.15 M in osmotic pressure calculation. What is the van’t Hoff factor?

Answer: i = 0.15 / 0.1 = 1.5

Question 14

Freezing point of a solution of 10 g urea in 180 g of water is?
(Kf = 1.86 K kg/mol, Molar mass of urea = 60 g/mol)

Answer: ฮ”Tf = 1.86 × (10/60) / (0.18) ≈ 1.72 K; Tf = -1.72°C

Question 15

Which factor decides magnitude of colligative properties?
A. Nature of solute
B. Number of solute particles
C. Volume of solvent
D. Temperature

Answer: B. Number of solute particles

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