Why Chemical Equation is Used to Find Molecularity and Strength of KMnO4 Using M/20 Mohr’s Salt Solution
In volumetric analysis, especially in Class 11 and Class 12 chemistry practicals, potassium permanganate (KMnO4) is commonly standardized using M/20 Mohr’s salt solution. A very common question asked in exams is:
“Why is a chemical equation required to find the molecularity and strength of KMnO4?”
The answer lies in the stoichiometry of the reaction and the nature of KMnO4.
1. Importance of Chemical Equation in Volumetric Analysis
In titration calculations, we do not depend only on the volume of solutions. All calculations are based on the balanced chemical equation.
KMnO4 does not react with Mohr’s salt in a simple 1:1 ratio. Therefore, without a chemical equation:
- The reaction ratio cannot be known
- The number of electrons transferred cannot be determined
- The equivalent weight and n-factor cannot be calculated
Hence, a chemical equation is compulsory to calculate the molecularity and strength of KMnO4.
2. Why Mohr’s Salt is Used
Mohr’s salt (FeSO4·(NH4)2SO4·6H2O) is used because:
- It is a primary standard
- It has high purity
- It has stable composition
- Its molarity (M/20) is accurately known
KMnO4 is not a primary standard because it decomposes on standing and may contain impurities. Therefore, KMnO4 solution must be standardized using Mohr’s salt.
3. Chemical Equation of the Reaction
The titration is carried out in acidic medium using dilute sulphuric acid. The balanced ionic equation is:
MnO4− + 5Fe2+ + 8H+ → Mn2+ + 5Fe3+ + 4H2O
From the above equation, we observe that:
- 1 mole of KMnO4 reacts with 5 moles of Fe2+
- KMnO4 acts as an oxidizing agent
- Mohr’s salt acts as a reducing agent
4. Determination of Molecularity (Molarity / Normality)
From the chemical equation, it is clear that one mole of KMnO4 gains five electrons. Therefore:
n-factor of KMnO4 = 5
Using the titration formula:
N1V1 = N2V2
The normality of Mohr’s salt is known, and the volumes are measured experimentally. Using this equation, the normality of KMnO4 is calculated.
Molarity of KMnO4 is then obtained using:
M = N / n-factor
5. Determination of Strength of KMnO4
Once the molarity of KMnO4 is known, its strength is calculated by:
Strength (g/L) = Molarity × Molar Mass
Molar mass of KMnO4 = 158 g mol−1
Thus, the strength of KMnO4 solution can be accurately determined.
6. Why Chemical Equation is Essential (Exam Point)
- To know the exact reaction ratio
- To calculate the n-factor of KMnO4
- To determine molarity and strength correctly
- Because the reaction is not 1:1
7. One-Line Board Answer
Chemical equation is used because KMnO4 reacts with Mohr’s salt in a fixed stoichiometric ratio, which is necessary to calculate the molecularity and strength of KMnO4.
Prepared for educational and examination purposes.
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